Hi Everyone,
OK, now that you have begun formulating a topic of interest, we will begin to build an initial portfolio. In the coming weeks, let’s see how they stack up as we learn more about research traditions. Module 2 is about research design and quantitative research.
Here is the data set with which we worked in class: Dummy Data
Here is the key to the quantitative activity we did in class for future reference: Dummy-Data_KEY
Module 2: EDUC_612_Fall_2019_Module_2
Here is a Screencast about how to get journal articles from ILLiad
Here are elements of a research article that can be used for both traditions: How to Write up a Research Report
Todd
Normal Distribution link: Interactive normal distribution curve
Hi Everyone,
Please post task 2’s answers here. Be sure to do your own work before posting and responding. 🙂
This is what I got for topic 3 task:
mode is 92
median is 92
mean is 92
variance is 27.5
the standard deviations is 5.24
Here is what I got for the following data set:
Scores: 85 86 87 92 92 92 97 98 99
Mode: 92; The mode is the value that appears most frequently. With this definition, the value that appears the most is 92.
Median: 92; The median is the midpoint of values from the set of values provided. Because the values were already ordered from lowest to highest and there was an odd number of values (9), I looked for the value that was in the middle of the order, and found that to be 92.
Mean: 92; The mean is the average value of the set. I found this by adding all the values (85+86+87+92+92+92+97+98+99=828), and dividing it by the total values present (9). 828/9 = 92
Variance: 24.4; The variance is the amount of spread among scores in a set when the mean is used as a measure of central tendency. At this point I already found the mean value, so to find the variance I started with finding the difference of each value from the mean, then square root of each difference, summed all the squared values, and divided that sum by the total amount of values (see below)
Score difference Squared value
85-92=-7 – 7^2=49
86-92=-6 – 6^2 =36
87-92=-5 – 5^2 =25
92-92=0 0^2 =0
92-92=0 0^2 =0
92-92=0 0^2 =0
97-92=5 5^2 =25
98-92=6 6^2 =36
99-92=7 7^2 =49
Sum of squared value= 49+36+25+0+0+0+25+36+49=220
Divided sum value=220/9=24.4
Standard Deviation: 4.94; Standard Deviation is found by taking the square root of the variance √(24.4)=4.94
Mode= 92
Median= 92
Mean= 92
Variance= 24.444
Standard Deviation= 4.944
For the mode (the most occurring number) I got 92.
For the median (the middle score) I got 92.
For the mean (the average) I got 92.
For the variance I got 24.44
For the standard deviation (the square root of the variance) I got 4.94.
Alright, let’s see if my math skills are correct! I am definitely rusty!!
Mode: 92
Median: 92
Mean: 92
Variance: 24.4
Standard Deviation: 4.9
mode: 92
median: 92
mean: 92
variance: 24.4
standard deviation: 4.94
All I can say is, I hope I did this right…
For the data set in Task 3 I found a mean, median and mode of 92. The variance was 24.4, with a Standard Deviation of 4.94
Mode: 92
Median: 92
Mean: 92
Range: 14
Variance: 24.44 (24.44444444444444)
Standard Deviation: 4.944 (4.94413)
85 86 87 92 92 92 97 98 99
mode = 92
median = 92
mean = 92
variance = 24.4444444444
standard deviation = 4.94413232473
Hope that does the trick.
Scores: 85 86 87 92 92 92 97 98 99
The mode is the number that occurs most often. The number that occurs the most is 92.
The median is the middle number, which is also 92.
The mean is the average of the numbers which is also 92.
Finding the variance tells us the amount of spread among the set of data. To find this find the difference between each number and the mean, square each difference, find the sum of the squares and then divide by the number of scores.
IE
85-92= -7. -7^2 = 49
86-92= -6. -6^2 = 36
87-92= -5. -5^2= 25
92-92 = 0
92-92= 0
92- 92=0
97-92= 5. 5^2 =25
98 -92 =6. 6^2 =36
99-92 = 7. 7^2 =49
Sum of all those numbers is 220. Divided by the number of sums (10). That equals 24.44~
Standard deviation is pretty much how spread out the set of numbers is. If the standard deviation is high, it means the numbers are spread out further. If it is a lower number, then they are a closer set of number. We find this by taking the square root of our variance. That would be around 4.94413.
Math is fun! 🙂
Here’s what I found:
Mode = 92
Median = 92
Mean = 92
Variance = 24.444
Standard Deviation = 4.944
This says task 2 but I am assuming it is for task 3?
I hope so because here is my task 3 answer 🙂
The data set on task 3: Mode = 92, Median = 92, Mean = 92, Variance = 24.22, and Standard Deviation = 4.94
Topic 3 Task Answers:
Mode = 92
Median = 92
Mean = 92
Variance = 24.4
Standard Deviation = 4.94
Task 3, Tasks.
The mean, median, and mode all equal 92. I hope. 92 Is right in the middle. The number 92 occurs the most or three times. Mean is 92, which is the sum of the numbers divided by 9. I plugged the numbers into the equation and got 24.44 as the variation and the standard deviation is 4.94~. It looks right since all the numbers are within 1 standard deviation of the mean. The numbers are bunched up together.
Kinda nice to do a little math quiz in the middle of my research class, but whatever:
regarding the set of
85, 86, 87, 92, 92, 92, 97, 98, 99
the mean, median and mode were all the same value of 92, the variance of the 9 values was 24.4 or 24 and 4 ninths, and the standard deviation was about 4.944-ish.
Hi everyone!
Here are the answers that I got from the data set in topic 3.
Mode: 92
Median: 92
Mean: 92
Variance: 24.4
Standard Deviation: 4.94
I hope these are right! Let me know if any of you got anything different 🙂
– Sam
“Differential ratings of and maternal impact on anxiety and depression among African American children in special education” by author Kristen F. Bean
This was a study conducted using questionnaires given to parents and teachers, and special education data collected from schools over a 12 year peiod. The sample size was 2 million children. Most of the children examined were from low-income African American families. The stated purpose was to determine differences between children’s self-reports, and mothers’, and teachers’ ratings of internalizing behaviors among low-income, African American children in special education. The study found that children self-reported internalized anxiety at higher rates than that of parents and educators, in particular black girls. The Mothers were found to have lower mastery than their white peers, which is believed to be why they had lower rates of reporting their kids having internalized anxiety. The study called for better training of teachers and educators and assisting low-income parents with developing mastery. My criticism of the studies conclusions are that it ignores the endearing affect on the part of these white mostly female teachers who show maternal care about the mental health of these children, because they are addressing an emotional need that goes unaddressed by their lesser educated parents. My additional criticism is the conclusion that the parents lacked mastery. Mothers of children with developmental disabilities tend to struggle with grief, shame, and self doubt, because they have bore child unhealthy. That experience affected their sense of mastery, and now they have to reconfigure their entire life plan, for which there is no clear blueprint.
Mode: 92
Median: 92
Mean: 92
Variance: 24.44(4444…)
Standard Deviation: 4.9436(8283772)